2sin^2(x)+3sinx+1=0

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Solution for 2sin^2(x)+3sinx+1=0 equation:


Simplifying
2sin2(x) + 3sinx + 1 = 0

Multiply in2s * x
2in2sx + 3sinx + 1 = 0

Reorder the terms:
1 + 3insx + 2in2sx = 0

Solving
1 + 3insx + 2in2sx = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 3insx + -1 + 2in2sx = 0 + -1

Reorder the terms:
1 + -1 + 3insx + 2in2sx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 3insx + 2in2sx = 0 + -1
3insx + 2in2sx = 0 + -1

Combine like terms: 0 + -1 = -1
3insx + 2in2sx = -1

Reorder the terms:
1 + 3insx + 2in2sx = -1 + 1

Combine like terms: -1 + 1 = 0
1 + 3insx + 2in2sx = 0

The solution to this equation could not be determined.

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